Mathematics · Study Guide

The Pythagorean Theorem: Statement, Proof, and Worked Examples

The Pythagorean theorem describes a fixed relationship between the three sides of any right triangle. It's one of the oldest theorems in mathematics and still one of the most useful — it shows up in geometry, trigonometry, physics, and everyday distance calculations.

The Statement

In a right triangle, let aa and bb be the two legs (the sides forming the right angle) and cc be the hypotenuse (the longest side, opposite the right angle). The theorem states:

a2+b2=c2a^2 + b^2 = c^2
This ONLY works for right triangles — applying it to any other triangle gives a wrong answer.

Why It's True (A Real Proof)

Here's one classic way to see why the theorem holds, using areas instead of algebra alone. Take four identical copies of the right triangle (legs aa, bb; hypotenuse cc) and arrange them inside a large square of side length (a+b)(a+b), with each triangle's right angle in a corner of the big square and the hypotenuses forming a smaller, tilted square in the middle.

The big square's area can be measured two different ways. Directly, its area is (a+b)2(a+b)^2. But it's also made up of the 4 triangles plus the inner tilted square, so its area is also 4⋅(12ab)+c24 \cdot (\frac{1}{2}ab) + c^2, which simplifies to 2ab+c22ab + c^2.

Since both expressions measure the exact same area, they must be equal:

(a+b)2=2ab+c2(a+b)^2 = 2ab + c^2
Expanding the left side:
a2+2ab+b2=2ab+c2a^2 + 2ab + b^2 = 2ab + c^2
Subtracting 2ab2ab from both sides leaves exactly the theorem:
a2+b2=c2a^2 + b^2 = c^2

Worked Example — Finding the Hypotenuse

Problem
A right triangle has legs of length 33 and 44. Find the hypotenuse.
Set up
Using a2+b2=c2a^2 + b^2 = c^2 with a=3a=3 and b=4b=4:
32+42=c23^2 + 4^2 = c^2
Simplify
9+16=c29 + 16 = c^2
25=c225 = c^2
Solve
Take the square root of both sides — remember to do this LAST, after combining the squares, not before:
c=25=5c = \sqrt{25} = 5

Common Mistakes

Practice

A right triangle has a hypotenuse of 1313 and one leg of 55. Find the other leg.
a2+52=132a^2 + 5^2 = 13^2
a2=169−25=144a^2 = 169 - 25 = 144
a=12a = 12
A ladder 10 m long leans against a wall, with its base 6 m from the wall. How high up the wall does it reach?
The ladder is the hypotenuse.
62+h2=1026^2 + h^2 = 10^2
h2=100−36=64h^2 = 100 - 36 = 64
h=8 mh = 8 \text{ m}

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